Perimeter = 54 = P
P=2L+2W
54=2*4N + 2*5N (N IS THE MULTIPLIER FOR THE RATIO VALUES.)
54= 8N + 10N
54=18N
18N=54
N=54/18
N=3 ANS. FOR THE MULTIPLIER.
4*3=12 FOR THE LENGTH.
5*3=15 FOR THE WIDTH.
PROOF:
54=2*12+2*15
54=24+30
54=54
On Sun, Aug 28, 2011 at 6:14 PM, mc100402505 Sheher Bano <mc100402505@vu.edu.pk> wrote:
a certain rectangle has a perimeter of 54. if the ratio of the length of the rectangle to the width is 5 to 4 , what is the length of the rectangle ? --
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