Re: [ vuZs.net ] BS (Computer Sciecce)

Assignment 1(Fall 2011)

Q.1

Find the equivalent resistance at point a, b of given circuit. Write each step of the calculation to get maximum marks. Draw the circuit diagram of each step otherwise you will lose your marks.

1) On the right side 2 ohm and 2 ohm resistors are in series so total resistance = 2 + 2 = 4ohms
Replace the two resistors with a single 4 ohm resistor
2) Now 4 ohm and 4 ohm resistor are in series so total resistance = 4 + 4 =8 ohms
Replace the two resistors with a single 8 ohm resistor
3) Now 8 ohm resistor is in series with 6 ohm resistor, so TR = 8 + 6 = 14 ohms
Replace the two resistors with a single 14 ohm resistor
4) Now 14 ohm resistor is in parallel with 8 ohm resistor so TR = 14.8/14+8 = 112/22 = 5 ohms approx.
Replace the two resistors with a single 5 ohm resistor
5) Now the 5 ohm and 5ohm resistor are in series so TR = 5 + 5 = 10 ohms

Q.2
Using the division rule, find V and I mentioned in the given circuit.


Using division rule of current:
1) Current I along 2 ohm resistor is (4/4+2) x 12A = (4/6) x 12 =  0.666 x 12= 8 A approx
so V = IR = 8x 2 = 16V
2) Current along 4 ohm resistor is (2/4+2) x 12 = (2/6) x 12 = 4 A
so I = 4A

Q.3
For the given circuit below, find current flow through each element, for the case when

1. Point a, b is open.
2. Point a, b is closed.

Please try to solve this by yourself. It is very easy.
Hint when point a,b is open I2 and I3 = 0
use the following formulae:
Power (watt)  = V x I
Current divider rule as in Q2.



Also draw the circuits yourselves. If you still have problem then email me.
bc100401927@vu.edu.pk

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